![Ex 6.3, 13 - Chapter 6 Class 10 Triangles - Part 2](https://d1avenlh0i1xmr.cloudfront.net/92e19755-b9b1-430c-82ca-fe2970c3767d/slide36.jpg)
Ex 6.3
Last updated at April 16, 2024 by Teachoo
Ex 6.3, 13 D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA2 = CB.CD Given: ABC where ADC = BAC To Prove: CA2 = CB.CD i.e. / = / Proof:- In BAC and ADC ACB = ACD BAC = ADC Hence by AA similarity criterion BAC ADC BAC ADC Hence / = / = / Hence / = / AC2 = BC . CD Hence proved