Ex 6.3, 13 - Chapter 6 Class 10 Triangles (Term 1)
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 6.3, 13 D is a point on the side BC of a triangle ABC such that ADC = BAC. Show that CA2 = CB.CD Given: ABC where ADC = BAC To Prove: CA2 = CB.CD i.e. / = / Proof:- In BAC and ADC ACB = ACD BAC = ADC Hence by AA similarity criterion BAC ADC BAC ADC Hence / = / = / Hence / = / AC2 = BC . CD Hence proved
Ex 6.3
Ex 6.3, 1 (i)
Ex 6.3, 1 (ii)
Ex 6.3, 1 (iii)
Ex 6.3, 1 (iv)
Ex 6.3, 1 (v) Important
Ex 6.3, 1 (vi)
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Ex 6.3, 13 Important You are here
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