Ex 6.3, 5 -  S and T are points on sides PR and QR of PQR - AA Similarity

  1. Chapter 6 Class 10 Triangles
  2. Serial order wise
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Ex 6.3, 5 S and T are points on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ∼ ΔRTS. Given: ∆ 𝑃𝑄𝑅 and the points S and T on sides PR and QR. Such that ∠P = ∠RTS To Prove: ΔRPQ ∼ ΔRTS. Proof: In ΔRPQ and ΔRTS. ∠P = ∠RTS And ∠PRQ = ∠TRS = ∠ R So, ΔRPQ ∼ ΔRTS. Hence proved

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.