Ex 6.3, 5
Last updated at Dec. 8, 2016 by Teachoo
Transcript
Ex 6.3, 5 S and T are points on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ∼ ΔRTS. Given: ∆ 𝑃𝑄𝑅 and the points S and T on sides PR and QR. Such that ∠P = ∠RTS To Prove: ΔRPQ ∼ ΔRTS. Proof: In ΔRPQ and ΔRTS. ∠P = ∠RTS And ∠PRQ = ∠TRS = ∠ R So, ΔRPQ ∼ ΔRTS. Hence proved
Chapter 6 Class 10 Triangles
Serial order wise
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CA Maninder Singh
CA Maninder Singh is a Chartered Accountant for the past 8 years. He provides courses for Practical Accounts, Taxation and Efiling at teachoo.com .