1. Chapter 6 Class 10 Triangles
  2. Serial order wise
  3. Ex 6.3

Ex 6.3, 5 - Class 10

Last updated at May 29, 2018 by

Ex 6.3, 5 - S and T are points on sides PR and QR of PQR - AA Similarity

  1. Chapter 6 Class 10 Triangles
  2. Serial order wise
    3. Ex 6.3
    Ex 6.4 →
Ask Download

Transcript

Ex 6.3, 5 S and T are points on sides PR and QR of ΔPQR such that ∠P = ∠RTS. Show that ΔRPQ ∼ ΔRTS. Given: ∆ 𝑃𝑄𝑅 and the points S and T on sides PR and QR. Such that ∠P = ∠RTS To Prove: ΔRPQ ∼ ΔRTS. Proof: In ΔRPQ and ΔRTS. ∠P = ∠RTS And ∠PRQ = ∠TRS = ∠ R So, ΔRPQ ∼ ΔRTS. Hence proved

Chapter 6 Class 10 Triangles
Serial order wise

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.