If ∆ ABC ~ ∆ QRP,  (ar (ABC))/(ar (PQR))=9/4 , AB = 18 cm and BC = 15 cm, then PR is equal to

(A) 10 cm 

(B) 12 cm 

(C) 20/3  cm   

(D) 8 cm

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  1. Chapter 6 Class 10 Triangles (Term 1)
  2. Serial order wise

Transcript

Question 13 If ∆ ABC ~ ∆ QRP, (ar (ABC))/(ar (PQR))=9/4 , AB = 18 cm and BC = 15 cm, then PR is equal to (A) 10 cm (B) 12 cm (C) 20/3 cm (D) 8 cm Our triangles look like We know that For similar triangles, ratio of Area of triangle is equal to the ratio of square of corresponding sides (𝐴𝑟𝑒𝑎 𝑜𝑓 ∆ 𝐴𝐵𝐶)/(𝐴𝑟𝑒𝑎 𝑜𝑓 ∆ 𝑃𝑄𝑅)=(𝐵𝐶)^2/(𝑃𝑅)2 9/4=(𝐵𝐶/𝑃𝑅)^2 (3/2)^2=(15/𝑃𝑅)^2 3/2=15/𝑃𝑅 PR = 2/3 × 15 PR = 2 × 5 PR = 10 cm So, the correct answer is (A)

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Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.