If ∆ ABC ~ ∆ QRP, (ar (ABC))/(ar (PQR))=9/4 , AB = 18 cm and BC = 15 cm, then PR is equal to
(A) 10 cm
(B) 12 cm
(C) 20/3 cm
(D) 8 cm

Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
NCERT Exemplar - MCQ
Question 2 Important
Question 3
Question 4 Important
Question 5 Important
Question 6 Important
Question 7
Question 8 Important
Question 9
Question 10 Important Deleted for CBSE Board 2024 Exams
Question 11
Question 12 Important
Question 13 Deleted for CBSE Board 2024 Exams You are here
Question 14 Important
Last updated at May 29, 2023 by Teachoo
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Question 13 If ∆ ABC ~ ∆ QRP, (ar (ABC))/(ar (PQR))=9/4 , AB = 18 cm and BC = 15 cm, then PR is equal to (A) 10 cm (B) 12 cm (C) 20/3 cm (D) 8 cm Our triangles look like We know that For similar triangles, ratio of Area of triangle is equal to the ratio of square of corresponding sides (𝐴𝑟𝑒𝑎 𝑜𝑓 ∆ 𝐴𝐵𝐶)/(𝐴𝑟𝑒𝑎 𝑜𝑓 ∆ 𝑃𝑄𝑅)=(𝐵𝐶)^2/(𝑃𝑅)2 𝟗/𝟒=(𝑩𝑪/𝑷𝑹)^𝟐 (3/2)^2=(15/𝑃𝑅)^2 𝟑/𝟐=𝟏𝟓/𝑷𝑹 PR = 2/3 × 15 PR = 2 × 5 PR = 10 cm So, the correct answer is (A)