NCERT Exemplar - MCQ

Chapter 6 Class 10 Triangles
Serial order wise

## (A) 9Β  (B) 3Β  (C) 1/3Β  (D) 1/9

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Question 10 It is given that β ABC ~ β PQR, with BC/QR = 1/3. Then, (ππ (πππ))/(ππ (π΅πΆπ΄)) is equal to (A) 9 (B) 3 (C) 1/3 (D) 1/9 We know that For similar triangles, ratio of Area of triangle is equal to the ratio of square of corresponding sides (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ)=(π΅πΆ)^2/(ππ)2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ)=(π΅πΆ/ππ)^2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ)=(1/3)^2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ)=1/9 But, we need to find ratio (ππ (πππ))/(ππ (π΅πΆπ΄)) (ππ (π·πΉπΈ))/(ππ (π©πͺπ¨)) = 9 So, the correct answer is (A)