It is given that β ABC ~ β PQR, with BC/QR = 1/3. Then, (ar (PRQ))/(ar (BCA)) is equal to
(A) 9Β (B) 3Β (C) 1/3Β (D) 1/9
NCERT Exemplar - MCQ
Last updated at Oct. 20, 2021 by Teachoo
Question 10 It is given that β ABC ~ β PQR, with BC/QR = 1/3. Then, (ππ (ππ π))/(ππ (π΅πΆπ΄)) is equal to (A) 9 (B) 3 (C) 1/3 (D) 1/9 We know that For similar triangles, ratio of Area of triangle is equal to the ratio of square of corresponding sides (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ )=(π΅πΆ)^2/(ππ )2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ )=(π΅πΆ/ππ )^2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ )=(1/3)^2 (π΄πππ ππ β π΄π΅πΆ)/(π΄πππ ππ β πππ )=1/9 But, we need to find ratio (ππ (ππ π))/(ππ (π΅πΆπ΄)) (ππ (π·πΉπΈ))/(ππ (π©πͺπ¨)) = 9 So, the correct answer is (A)