Question 4
The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is
9 cm (B) 10 cm
(C) 8 cm (D) 20 cm
In a Rhombus
Sum of squares of sides = Sum of its diagonals
(For proof, check Ex 6.5, 7 – Chapter 6 Class 10 Triangles)
Thus,
AB2 + BC2 + CD2 + AD2 = AC2 + BD2
Since all sides of Rhombus are equal, our equation becomes
AB2 + AB2 + AB2 + AB2 = AC2 + BD2
4AB2 = AC2 + BD2
Putting length of diagonals as 16 and 12 cm
4AB2 = 162 + 122
4AB2 = 256 + 144
4AB2 = 400
AB2 = 400/4
AB2 = 100
AB2 = 102
AB = 10 cm
So, the correct answer is (B)
So, the correct answer is (B)
Made by
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths and Science at Teachoo.
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