Question 4
The lengths of the diagonals of a rhombus are 16 cm and 12 cm. Then, the length of the side of the rhombus is
9 cm (B) 10 cm
(C) 8 cm (D) 20 cm
In a Rhombus
Sum of squares of sides = Sum of its diagonals
(For proof, check Ex 6.5, 7 – Chapter 6 Class 10 Triangles)
Thus,
AB2 + BC2 + CD2 + AD2 = AC2 + BD2
Since all sides of Rhombus are equal, our equation becomes
AB2 + AB2 + AB2 + AB2 = AC2 + BD2
4AB2 = AC2 + BD2
Putting length of diagonals as 16 and 12 cm
4AB2 = 162 + 122
4AB2 = 256 + 144
4AB2 = 400
AB2 = 400/4
AB2 = 100
AB2 = 102
AB = 10 cm
So, the correct answer is (B)
So, the correct answer is (B)

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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