Question 2 - NCERT Exemplar - MCQ - Chapter 6 Class 10 Triangles

Last updated at April 16, 2024 by

D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE ∥ BC. Then, length of DE (in cm) is

(A) 2.5  

(B) 3  

(C) 5  

(D) 6

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Question 2 D and E are respectively the points on the sides AB and AC of a triangle ABC such that AD = 2 cm, BD = 3 cm, BC = 7.5 cm and DE ∥ BC. Then, length of DE (in cm) is (A) 2.5 (B) 3 (C) 5 (D) 6 Since DE ∥ BC ∠ ADB = ∠ ABD ∠ AED = ∠ ACB Thus, by AA Similarity Δ ADE ~ Δ ABC (Corresponding angles) (Corresponding angles) Since sides are proportional in similar triangles 𝐴𝐷/𝐴𝐵=𝐷𝐸/𝐵𝐶 𝟐/(𝟐 + 𝟑)=𝑫𝑬/(𝟕.𝟓) 2/5=𝐷𝐸/7.5 2/5 × 7.5 = DE 2 × 1.5 = DE 3 = DE DE = 3 cm So, the correct answer is (B)

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