Laws of Refraction

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Example Suppose for a ray of Light. Angle of Incidence = 37° and Angle of Refraction = 24°. Find Refractive Index (Given: sin 37° = 0.6 and sin 24° = 0.4) We know that Refractive Index = (𝑠𝑖𝑛 (𝐴𝑛𝑔𝑙𝑒 𝑜𝑓 𝑖𝑛𝑐𝑖𝑑𝑒𝑛𝑐𝑒))/(𝑠𝑖𝑛 (𝐴𝑛𝑔𝑙𝑒 𝑜𝑓 𝑟𝑒𝑓𝑟𝑎𝑐𝑡𝑖𝑜𝑛)) Refractive Index = (𝑠𝑖𝑛 (37°))/(𝑠𝑖𝑛 (24°)) Refractive Index = 0.6/0.4 Refractive Index = 6/4 Refractive Index = 3/2 Refractive Index = 1.5 Example A beam of light passes from air into a substance X. If the angle of incidence be 72° and the angle of refraction be 40°, calculate the refraction index of substance X. (Given: sin 72° = 0.951 and sin 40° = 0.642 ) Given, Angle of incidence = ∠i = 72° Angle of Refraction = ∠r = 40° We have to find Refraction index of substance X By second law of refraction, Refractive index = sin⁡𝑖/sin⁡𝑟 = sin⁡〖72°〗/sin⁡〖40°〗 = 0.951/0.642 = 951/642 = 317/214 = 1.48 Refractive index of substance X is 1.48