Ex 7.1, 18 - Chapter 7 Class 12 Integrals
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Ex 7.1, 18 Find anti derivative of ∫1▒〖sec𝑥 (sec〖𝑥+tan𝑥 〗)〗dx ∫1▒〖𝑠𝑒𝑐𝑥 (𝑠𝑒𝑐〖𝑥+𝑡𝑎𝑛𝑥 〗)〗 𝑑𝑥 =∫1▒〖 (〖𝑠𝑒𝑐〗^2〖𝑥+〖𝑠𝑒𝑐 𝑥 𝑡𝑎𝑛〗𝑥 〗)〗 𝑑𝑥 =∫1▒〖〖𝑠𝑒𝑐〗^2 𝑥 𝑑𝑥+ 〗 ∫1▒(𝑠𝑒𝑐 𝑥 𝑡𝑎𝑛𝑥 ) 𝑑𝑥 =𝒕𝒂𝒏𝒙+𝒔𝒆𝒄𝒙+𝑪 As ∫1▒〖sec^2𝑥 𝑑𝑥=tan𝑥 〗+𝐶 & ∫1▒sec𝑥tan𝑥 𝑑𝑥=sec𝑥+𝐶
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