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Ex 7.1, 5 Find anti derivative of sin⁑2π‘₯ – 4𝑒3π‘₯ Subtracting (1) & (2) sin⁑2π‘₯βˆ’γ€–4𝑒〗^3π‘₯=(βˆ’1)/2 (cos⁑2π‘₯ )^β€²βˆ’ 4/3 (𝑒^3π‘₯ )^β€² We know that (cos⁑2π‘₯ )^β€²=βˆ’2 sin⁑2π‘₯ (βˆ’1)/2 (cos⁑2π‘₯ )^β€²=sin⁑2π‘₯ 𝐬𝐒𝐧 πŸπ’™=(βˆ’πŸ)/𝟐 (π’„π’π’”β‘πŸπ’™ )^β€² We know that (𝑒^3π‘₯ )^β€²=𝑒^3π‘₯ . 3 β‡’ γ€–1(𝑒^3π‘₯ )γ€—^β€²/3=𝑒^3π‘₯ ⇒𝑒^3π‘₯=γ€–1(𝑒^3π‘₯ )γ€—^β€²/3 β‡’γ€–πŸ’π’†γ€—^πŸ‘π’™=πŸ’/πŸ‘ (𝒆^πŸ‘π’™ )^β€² …(2) =(βˆ’1/2 cos⁑2π‘₯βˆ’4/3 𝑒^3π‘₯ )^β€² ∴ Anti derivative is (βˆ’πŸ)/𝟐 π’„π’π’”β‘πŸπ’™βˆ’ πŸ’/πŸ‘ 𝒆^πŸ‘π’™

  1. Chapter 7 Class 12 Integrals
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo