Last updated at Dec. 16, 2024 by Teachoo
Ex 7.1, 1 Find anti derivative of sin 2x We know that γ (cosβ‘γ π₯γ )γ^β²=γβsinγβ‘π₯ γ (ππ¨π¬β‘γ ππγ )γ^β²=γβπ¬π’π§γβ‘ππ Γ π (β1)/( 2) (cosβ‘γ 2π₯γ )^β²=sinβ‘2π₯ sinβ‘2π₯=(β1)/( 2) (cosβ‘2π₯ )^β² sinβ‘2π₯=((β1)/( 2) cosβ‘2π₯ )^β² β΄ Anti derivate of π ππβ‘2π₯=(βπ)/π ππ¨π¬β‘ππ
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo