1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise
  3. Ex 2.2
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Question 5 - Ex 2.2 - Chapter 2 Class 12 Inverse Trigonometric Functions

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Question 5 If sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 , then find the value of x. Given sin ("sin−1 " 1/5 " + cos−1 x" ) = 1 Putting sin 𝜋/2 = 1 sin ("sin−1 " 1/5 " + cos−1 x" ) = sin π/2 Comparing angles "sin−1 " 1/5 + "cos−1 x" = 𝜋/2 "sin−1 " 1/5 = 𝝅/𝟐 – "cos−1 x" We know that sin"−"1 x + cos"−"1 x = 𝜋/2 sin"−"1 x = 𝜋/2 – cos"−"1 x sin-1 1/5 = sin"−"1 x Thus, we can write 1/5 = x x = 𝟏/𝟓 Hence, x = 1/5
  1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise

    3. Ex 2.2

    Examples →
Examples →
Chapter 2 Class 12 Inverse Trigonometric Functions
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo