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Ex 2.2, 6 Write the function in the simplest form: tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) , |x| < a tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) Let x = a sin 𝜽 = tan-1 ((a sin⁡θ)/√(a^2−(a sinθ)^2 )) = tan-1 ((a sin⁡θ)/√(a^2 − a^2 sin2θ)) = tan-1 ((a sin⁡θ)/√(a^2 (1 − sin^2 θ))) = tan-1 ((a sin⁡θ)/(a√(1 − sin^2 θ))) = tan-1 (sin⁡θ/√(cos^2 θ)) = tan-1 ((a sin⁡θ)/(a√(1 − sin^2 θ))) = tan-1 (sin⁡θ/√(cos^2 θ)) = tan-1 (sin⁡θ/〖 cos〗⁡θ ) = tan-1 (tan θ) = 𝛉 We assumed that x = a sin θ 𝑥/𝑎 = sin θ sin-1 𝒙/𝒂 = θ Hence, tan-1 𝑥/√(𝑎^2 − 𝑥^2 ) = θ = sin-1 𝒙/𝒂

  1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise

About the Author

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo