1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise
  3. Ex 2.2
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Question 3 - Ex 2.2 - Chapter 2 Class 12 Inverse Trigonometric Functions

Last updated at Dec. 16, 2024 by Teachoo

Transcript

Question 3 Write the function in the simplest form: tanβˆ’1 1/√(π‘₯^2βˆ’1), |x| > 1 tanβˆ’1 (1/√(π‘₯^2 βˆ’ 1)) Putting x = sec ΞΈ = tanβˆ’1 (1/√(〖𝒔𝒆𝒄〗^𝟐⁑𝜽 βˆ’ 1)) = tanβˆ’1 (1/√(γ€–(𝟏 + 〖𝒕𝒂𝒏〗^πŸγ€—β‘πœ½ ) βˆ’ 1)) = tanβˆ’1 (1/√(tan^2⁑θ )) = tanβˆ’1 (1/tan⁑θ ) We write 1/√(π‘₯^2 βˆ’ 1) in form of tan Whenever there is √(π‘₯^2βˆ’1) , we put x = sec ΞΈ = tanβˆ’1 (cot ΞΈ) = tanβˆ’1 tan (90 – ΞΈ) = 90 – ΞΈ = 𝝅/𝟐 – ΞΈ We assumed x = sec ΞΈ sec ΞΈ = x ΞΈ = sec-1 x Hence, our equation becomes tan-1 (1/√(π‘₯^2βˆ’1)) = πœ‹/2 – ΞΈ = 𝝅/𝟐 – secβˆ’1 x (cot ΞΈ = tan (90 – ΞΈ) )
  1. Chapter 2 Class 12 Inverse Trigonometric Functions
  2. Serial order wise

    3. Ex 2.2

    Examples →
Examples →
Chapter 2 Class 12 Inverse Trigonometric Functions
Serial order wise

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo