Question 5 - Examples - Chapter 9 Class 11 Straight Lines
Last updated at Dec. 16, 2024 by Teachoo
Last updated at Dec. 16, 2024 by Teachoo
Question 5 Equation of a line is 3x – 4y + 10 = 0. Find its (i) slope 3x – 4y + 10 = 0 −4y = −3x − 10 −4y = − (3x + 10) 4y = 3x + 10 y = (3𝑥 + 10)/4 y = 3/4 x + 10/4 y = 3/4x + 5/2 The above equation is of the form y = mx + c We convert it to y = mx + c where m is the slope & c is the y-intercept Here, m = 3/4 & c = 5/2 Hence, slope m = 𝟑/𝟒 & y-intercept = 5/2 Question 5 Equation of a line is 3x – 4y + 10 = 0. Find its (ii) x and y-intercepts. 3x – 4y + 10 = 0 3x − 4y = − 10 Dividing both sides by − 10 (3𝑥 − 4𝑦)/( −10) = ( −10)/( −10) 3𝑥/( −10) − 4𝑦/( −10) = 1 3𝑥/( −10) + 4𝑦/( 10) = 1 𝑥/(( −10)/3) + 𝑦/(10/4) = 1 𝑥/((−10)/3) + 𝑦/(5/2) = 1 The above equation of the form 𝑥/𝑎 + 𝑦/(𝑏 ) = 1 Hence, a = x-intercept = (−𝟏𝟎)/𝟑 & b = y-intercept = 𝟓/𝟐
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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo