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Ex 12.1, 2 (viii) - Chapter 12 Class 8 Factorisation

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Ex 14.1, 2 (viii) - Factorise - 4 a^2 + 4 ab - 4 ca - Teachoo

Ex 14.1, 2 (viii) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (viii) - Chapter 14 Class 8 Factorisation - Part 3

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Ex 12.1, 2 (Method 1) Factorise the following expressions. (viii) – 4π‘Ž^2 + 4 ab – 4 ca Now, – 4π‘Ž^2 = βˆ’4 Γ— π‘Ž^2 = βˆ’1 Γ— 4 Γ— π‘Ž^2 = βˆ’1 Γ— 2 Γ— 2 Γ— π‘Ž^2 = βˆ’1 Γ— 2 Γ— 2 Γ— a Γ— a 4ab = 4 Γ— a Γ— b = 2 Γ— 2 Γ— a Γ— b 4ca = 4 Γ— c Γ— a = 2 Γ— 2 Γ— c Γ— a So, 2, 2 and a are the common factors. – 4π‘Ž^2 + 4ab βˆ’4ca = (βˆ’1 Γ— 2 Γ— 2 Γ— a Γ— a) + (2 Γ— 2 Γ— a Γ— b) βˆ’ (2 Γ— 2 Γ— c Γ— a) Taking 2 Γ— 2 Γ— a common, = 2 Γ— 2 Γ— a Γ— ((βˆ’1 Γ— a) + b βˆ’ c) = 4a (βˆ’a + b βˆ’ c) Ex 12.1, 2 (Method 2) Factorise the following expressions. (viii) – 4π‘Ž^2 + 4 ab – 4 ca – 4π‘Ž^2 + 4 ab – 4 ca Taking 4 common, = 4 (β€“π‘Ž^2 + ab βˆ’ ca) = 4 ((βˆ’a Γ— a) + (a Γ— b) βˆ’ (c Γ— a)) Taking a common, = 4a (βˆ’a + b βˆ’ c)

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