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Ex 14.1, 2 (iii) - Factorise 7a^2 + 14a - Chapter 14 Class 8

Ex 14.1, 2 (iii) - Chapter 14 Class 8 Factorisation - Part 2

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Ex 12.1, 2 (Method 1) Factorise the following expressions. (iii) 7π‘Ž^2 + 14a 7π‘Ž^2 + 14a 7π‘Ž^2 = 7 Γ— π‘Ž^2 = 7 Γ— a Γ— a 14a = 14 Γ— a = 7 Γ— a Γ— a So, 7 and a are the common factors. 7π‘Ž^2 + 14a = (7 Γ— a Γ— a) + (2 Γ— 7 Γ— a) = (7 Γ— a) (a + 2) = 7a (a + 2) Ex 12.1, 2 (Method 2) Factorise the following expressions. (iii) 7π‘Ž^2 + 14a 7π‘Ž^2 + 14a = 7π‘Ž^2 + (7 Γ— 2) a = (7a Γ— a) + (7a Γ— 2) Taking 7a common, = 7a (a + 2)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.