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Ex 14.1, 2 (v) - Factorise  20 l^2 m + 30 a l m - Chapter 14 Class 8

Ex 14.1, 2 (v) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (v) - Chapter 14 Class 8 Factorisation - Part 3

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Ex 12.1, 2 (Method 1) Factorise the following expressions. (v) 20 𝑙^2 m + 30 a l m 20 𝑙^2 m = 20 Γ— 𝑙^2 Γ— m = 2 Γ— 2 Γ— 5 Γ— 𝑙^2 Γ— m = 2 Γ— 2 Γ— 5 Γ— l Γ— l Γ— m 30 alm = 30 Γ— a Γ— l Γ— m = 2 Γ— 3 Γ— 5 Γ— a Γ— l Γ— m So, 20 𝑙^2m = 2 Γ— 2 Γ— 5 Γ— l Γ— l Γ— m 30 alm = 2 Γ— 3 Γ— 5 Γ— a Γ— l Γ— m So, 2, 5, l and m are the common factors. Now, 20 𝑙^2m + 30 alm = (2 Γ— 2 Γ— 5 Γ— l Γ— l Γ— m) + (2 Γ— 3 Γ— 5 Γ— a Γ— l Γ— m) Taking 2 Γ— 5 Γ— l Γ— m common = 2 Γ— 5 Γ— l Γ— m (2 Γ— l + 3 Γ— a) = 10lm(2l + 3a) Ex 12.1, 2 (Method 2) Factorise the following expressions. (v) 20 𝑙^2 m + 30 a l m 20 𝑙^2 m + 30 a l m = (10 Γ— 2) 𝑙^2 m + (10 Γ— 3) alm Taking 10 common, = 10 Γ— (2𝑙^2m + 3 alm) = 10 Γ— ((2l Γ— lm) + (3a Γ— lm)) Taking lm common, = 10 Γ— lm (2l + 3a) = 10lm (2l + 3a)

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.