Ex 12.1, 2 (vii) - Factorise 10 a^2 - 15 b^2 + 20 c^2 - Teachoo - Ex 12.1

part 2 - Ex 12.1, 2 (vii) - Ex 12.1 - Serial order wise - Chapter 12 Class 8 Factorisation
part 3 - Ex 12.1, 2 (vii) - Ex 12.1 - Serial order wise - Chapter 12 Class 8 Factorisation

 

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Ex 12.1, 2 (Method 1) Factorise the following expressions. (vii) 10 š‘Ž^2 – 15 š‘^2 + 20 š‘^2 Now, 10š‘Ž^2= 10 Ɨ š‘Ž^2 = 2 Ɨ 5 Ɨ š‘Ž^2 = 2 Ɨ 5 Ɨ a Ɨ a 15š‘^2 = 15 Ɨ š‘^2 = 3 Ɨ 5 Ɨ š‘^2 = 2 Ɨ 5 Ɨ b Ɨ b 20š‘^2 = 20 Ɨ š‘^2 = 2 Ɨ 2 Ɨ 5 Ɨ š‘^2 = 2 Ɨ 2 Ɨ 5 Ɨ c Ɨ c So, 5 is the common factor. 10š‘Ž^2 – 15š‘^2 + 20š‘^2 = (2 Ɨ 5 Ɨ a Ɨ a) āˆ’ (3 Ɨ 5 Ɨ b Ɨ b) + (2 Ɨ 2 Ɨ 5 Ɨ c Ɨ c) Taking 5 common = 5 Ɨ ((2 Ɨ a Ɨ a) āˆ’ (3 Ɨ b Ɨ b) + (2 Ɨ 2 Ɨ c Ɨ c)) = 5 Ɨ (2š‘Ž^2 āˆ’ 3š‘^2 + 4š‘^2) = 5 (2š’‚^šŸ āˆ’ 3š’ƒ^šŸ + 4š’„^šŸ) Ex 12.1, 2 (Method 2) Factorise the following expressions. (vii) 10 š‘Ž^2 – 15 š‘^2 + 20 š‘^2 10 š‘Ž^2 – 15 š‘^2 + 20 š‘^2 = (5 Ɨ 2) š‘Ž^2 āˆ’ (5 Ɨ 3 ) š‘^2 + (5 Ɨ 4) š‘^2 Taking 5 common, = 5 (2š’‚^šŸ āˆ’ 3š’ƒ^šŸ + 4š’„^šŸ)

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