Check sibling questions

Ex 12.1, 2 (vi) - Chapter 12 Class 8 Factorisation

Last updated at May 18, 2023 by

Ex 14.1, 2 (vi) - Factorise 5 x^2 y - 15 xy^2 - Chapter 14 Class 8

Ex 14.1, 2 (vi) - Chapter 14 Class 8 Factorisation - Part 2
Ex 14.1, 2 (vi) - Chapter 14 Class 8 Factorisation - Part 3

Get live Maths 1-on-1 Classs - Class 6 to 12

Book 30 minute class for β‚Ή 499 β‚Ή 299

Transcript

Ex 12.1, 2 (Method 1) Factorise the following expressions. (vi) 5 π‘₯^2 y – 15 γ€–π‘₯𝑦〗^2 5 π‘₯^2 y = 5 Γ— π‘₯ Γ— π‘₯ Γ— y 15 π‘₯y^2 = 15 Γ— π‘₯ Γ— 𝑦^2 = 3 Γ— 5 Γ— π‘₯ Γ— 𝑦^2 = 3 Γ— 5 Γ— π‘₯ Γ— 𝑦 Γ— 𝑦 So, 5 π‘₯^2 y = 5 Γ— π‘₯ Γ— π‘₯ Γ— y 15π‘₯^2 y = 3 Γ— 5 Γ— π‘₯ Γ— π‘₯ Γ— y So, 5, π‘₯ and y are the common factors. Now, 5 π‘₯^2y – 15 γ€–π‘₯𝑦〗^2 = (5 Γ— π‘₯ Γ— π‘₯ Γ— y) βˆ’ (3 Γ— 5 Γ— π‘₯ Γ— y Γ— y) Taking 5 Γ— π‘₯ Γ— y common = 5 Γ— π‘₯ Γ— y (π‘₯ βˆ’ (3 Γ— y)) = 5xy (x βˆ’ 3y) Ex 12.1, 2 (Method 2) Factorise the following expressions. (vi) 5 π‘₯^2 y – 15 γ€–π‘₯𝑦〗^2 5 π‘₯^2y – 15 γ€–π‘₯𝑦〗^2 = 5 π‘₯^2y – 5 Γ— 3 Γ— γ€–π‘₯𝑦〗^2 Taking 5 Γ— π‘₯ Γ— y common = 5 (π‘₯^2y βˆ’ 3γ€–π‘₯𝑦〗^2) = 5 ((π‘₯𝑦 Γ— π‘₯) βˆ’ (π‘₯𝑦 Γ— 3y)) Taking xy common, = 5𝒙y (𝒙 βˆ’ 3y)

Ask a doubt
Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.