Ex 12.1, 2 (vi) - Factorise  5 x^2 y - 15 xy^2  - Chapter 14 Class 8 - Ex 12.1

part 2 - Ex 12.1, 2 (vi) - Ex 12.1 - Serial order wise - Chapter 12 Class 8 Factorisation
part 3 - Ex 12.1, 2 (vi) - Ex 12.1 - Serial order wise - Chapter 12 Class 8 Factorisation

 

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Ex 12.1, 2 (Method 1) Factorise the following expressions. (vi) 5 š‘„^2 y – 15 ć€–š‘„š‘¦ć€—^25 š‘„^2y – 15 ć€–š‘„š‘¦ć€—^2 = 5 š‘„^2y – 5 Ɨ 3 Ɨ ć€–š‘„š‘¦ć€—^2 Taking 5 common = 5 (š‘„^2y āˆ’ 3ć€–š‘„š‘¦ć€—^2) = 5 ((š’™š’š Ɨ š‘„) āˆ’ (š’™š’š Ɨ 3y)) Taking xy common, = 5š’™y (š’™ āˆ’ 3y) Ex 12.1, 2 (Method 2) Factorise the following expressions. (vi) 5 š‘„^2 y – 15 ć€–š‘„š‘¦ć€—^25 š’™^šŸ y = 5 Ɨ š‘„ Ɨ š‘„ Ɨ y 15 š’™š²^šŸ = 15 Ɨ š‘„ Ɨ š‘¦^2 = 3 Ɨ 5 Ɨ š‘„ Ɨ š‘¦^2 = 3 Ɨ 5 Ɨ š’™ Ɨ š’š Ɨ š’š So, 5 š‘„^2 y = 5 Ɨ š‘„ Ɨ š‘„ Ɨ y 15š‘„^2 y = 3 Ɨ 5 Ɨ š‘„ Ɨ š‘„ Ɨ y So, 5, š’™ and y are the common factors. Now, 5 š‘„^2y – 15 ć€–š‘„š‘¦ć€—^2 = (5 Ɨ š‘„ Ɨ š‘„ Ɨ y) āˆ’ (3 Ɨ 5 Ɨ š‘„ Ɨ y Ɨ y) Taking 5 Ɨ š’™ Ɨ y common = 5 Ɨ š‘„ Ɨ y (š‘„ āˆ’ (3 Ɨ y)) = 5xy (x āˆ’ 3y)

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