Integration by specific formulaes - Formula 3
Integration by specific formulaes - Formula 3
Last updated at July 14, 2026 by Teachoo
Transcript
Ex 7.4, 5 3š„/(1 + 2š„4) Let š„^2=š” Differentiating both sides 2š„=šš”/šš„ šš„=šš”/2š„ Integrating the function š¤.š.š”.š„ ā«1ā(3š„ )/(1 + 2š„^4 ) šš„ =ā«1ā3š„/(1 + 2(š„^2 )^2 ) šš„ Putting value of š„^2=š” and šš„=šš”/2š„ =ā«1ā3š„/(1 + 2š”^2 ) šš„ =ā«1ā3š„/(1 + 2š”^2 )Ćšš”/2š„ =3/2 ā«1āšš”/(1 + 2š”^2 ) =3/2 ā«1āšš”/2(1/2 + š”^2 ) =3/(2 . 2) ā«1āšš”/(1/2 + š”^2 ) =3/4 ā«1āšš”/(š”^2 + 1/2). šš” =3/4 ā«1āšš”/(š”^2 +(1/ā2)^2 ). šš”