Ex 6.3, 5 (i) - Chapter 6 Class 12 Application of Derivatives

Last updated at August 25, 2026 by

Ex 6.3, 5 (i) - For f(x) = x^3, x ∈ [-2, 2], find absolute maximum and - Ex 6.3

part 2 - Ex 6.3, 5 (i) - Ex 6.3 - Serial order wise - Chapter 6 Class 12 Application of Derivatives

 

 

Remove Ads Take short quiz All Quiz and Worksheets
Teachoo ¡ Class 12 Explore Class 12

Transcript

Ex 6.3, 5 Find the absolute maximum value and the absolute minimum value of the following functions in the given intervals: (i) f (𝑥) = 𝑥3, 𝑥∈[– 2, 2]Finding f’(𝒙) f’(𝑥)=𝑑(𝑥^3 )/𝑑𝑥 f’(𝑥)=3𝑥^2 Putting f’(𝒙)=𝟎 3𝑥^2=0 𝑥^2=0 𝑥=0 So, 𝑥=0 is critical point Since given interval is 𝑥 ∈ [−2 , 2] Hence calculating f(𝑥) at 𝑥=−2 , 0 , 2 Absolute Maximum value of f(x) is 8 at 𝒙 = 2 & Absolute Minimum value of f(x) is –8 at 𝒙 = –2

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh is an IIT Kanpur graduate and has been teaching for 16+ years. At Teachoo, he breaks down Maths, Science and Computer Science into simple steps so students understand concepts deeply and score with confidence.

Many students prefer Teachoo Black for a smooth, ad-free learning experience.