Ex 6.4, 9 The approximate change in the volume of a cube of side x meters caused by increasing the side by 3% is (A) 0.06 x3 m3 (B) 0.6 x3 m3 (C) 0.09 x3 m3 (D) 0.9 x3 m3Let side of the cube = x meters Increase in side = 3% = 0.03 x Hence, ∆x = 0.03 x Volume of the cube = V = x3 m3 We need to find approximate change in volume V of the cube i.e. ∆V Now, ∆V= 𝑑𝑣/𝑑𝑥 ∆x = (𝑑(𝑥^3))/𝑑𝑥 ∆x = 3x2 (0.03x) = 0.09 x3 So part (C) is the correct answer.

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.

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