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Ex 6.4,4 - Chapter 6 Class 12 Application of Derivatives (Term 1)

Last updated at April 15, 2021 by

Ex 6.4, 4 - Find approx change in volume V of a cube of side x

Ex 6.4,4 - Chapter 6 Class 12 Application of Derivatives - Part 2

Transcript

Ex 6.4, 4 Find the approximate change in the volume V of a cube of side x meters caused by increasing the side by 1%.Let side of the cube = x metres Increase in side = 1% = 0.01 x Hence, ∆x = 0.01 x Volume of the cube = V = x3 m3 We need to find approximate change in volume v of the cube i.e. ∆V Now, ∆V = 𝑑𝑣/𝑑𝑥 ∆x = (𝑑(𝑥^3))/𝑑𝑥 ∆x = 3x2 (0.01x) = 0.03 x3 Hence, the approximate change is 0.03 x3 m3.

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