
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Approximations (using Differentiation)
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Approximations (using Differentiation)
Last updated at May 29, 2023 by Teachoo
Question 2 Find the approximate value of f (2.01), where f (x) = 4x2 + 5x + 2.Let x = 2 and â x = 0.01 Given f(x) = 4x2 + 5x + 2 fâ(x) = 8x + 5 Now, âđŚ = fâ(x) â x = (8x + 5) 0.01 Also, ây = f (x + âx) â f(x) f(x + â x) = f (x) + âđŚ f (2.01) = 4x2 + 5x + 2 + (8x + 5)(0.01) Putting value of x = 2 đ (2.01)=4 (2)^2+ 5(2)+2+(0.01)[8(2)+5] = (16+10+2)+(21) (0.01) = 28+0.21 =28.21 Hence, the approximate value of f (2.01) is 28.21