1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise
  3. Ex 6.4

Ex 6.4,2 - Chapter 6 Class 12 Application of Derivatives

Last updated at Jan. 7, 2020 by

Check Full Chapter Explained - Continuity and Differentiability - Application of Derivatives (AOD) Class 12

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  1. Chapter 6 Class 12 Application of Derivatives
  2. Serial order wise

    3. Ex 6.4

    Ex 6.5 →

Transcript

Ex 6.4, 2 Find the approximate value of f (2.01), where f (x) = 4x2 + 5x + 2. Let x = 2 and โˆ† x = 0.01 Given f(x) = 4x2 + 5x + 2 fโ€™(x) = 8x + 5 Now, โˆ†๐‘ฆ = fโ€™(x) โˆ† x = (8x + 5) 0.01 Also, โˆ†y = f (x + โˆ†x) โˆ’ f(x) f(x + โˆ† x) = f (x) + โˆ†๐‘ฆ f (2.01) = 4x2 + 5x + 2 + (8x + 5)(0.01) Putting value of x=2 ๐‘“ (2.01)=4 (2)^2+ 5(2)+2+(0.01)[8(2)+5] = (16+10+2)+(21) (0.01) = 28+0.21 =28.21 Hence, the approximate value of f (2.01) is 28.21

Chapter 6 Class 12 Application of Derivatives
Serial order wise

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