Approximations (using Differentiation)
Last updated at August 14, 2026 by Teachoo
Transcript
Question 1 Using differentials, find the approximate value of each of the following up to 3 places of decimal. (xiii) ใ(81.5)ใ^(1/4)Let ๐ฆ=(๐ฅ)^( 1/4) where ๐ฅ=81 & โ๐ฅ=0. 5 Now, ๐ฆ=๐ฅ^( 1/4) Differentiating w.r.t.๐ฅ ๐๐ฆ/๐๐ฅ=๐(๐ฅ^( 1/4) )/๐๐ฅ=1/4 ๐ฅ^( 1/4 โ 1)=1/4 ๐ฅ^( (โ 3)/( 4)) =1/(4๐ฅ^(3/4) ) โ ๐ฅ Using โ๐ฆ=๐๐ฆ/๐๐ฅ โ๐ฅ โ๐ฆ=๐๐ฆ/(4๐ฅ^(3/4) ) โ๐ฅ Putting Values โ๐ฆ=1/(4(81)^( 3/4) ) ร (0. 5) โ๐ฆ=(0. 5)/(4 ร (3^( 4) )^( 3/4) ) โ๐ฆ=(0. 5)/(4 ร 3^( 3) ) โ๐ฆ=(0. 5)/(4 ร 27) โ๐ฆ=(0. 5)/108 โ๐ฆ=0. 0046 We know that โ๐ฆ=๐(๐ฅ+โ๐ฅ)โ๐(๐ฅ) So, โ๐ฆ=(๐ฅ+โ๐ฅ)^( 1/4)โ๐ฅ^( 1/4) Putting Values 0. 0046=(81+0. 5)^( 1/4)โ(81)^( 1/4) 0. 0046=(81. 5)^( 1/4)โ(3^4 )^( 1/4) 0. 0046=(81. 5)^( 1/4)โ3 0. 0046+3=(81. 5)^( 1/4) 3. 0046=(81. 5)^( 1/4) Thus, Approximate Value of (81. 5)^( 1/4) is ๐. ๐๐๐๐