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Ex 5.2, 1 - Chapter 5 Class 12 Continuity and Differentiability
Last updated at July 14, 2026 by Teachoo
Chapter 5 Class 12 Continuity and Differentiability
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Transcript
Ex 5.2, 1 Differentiate the functions with respect to π₯ sinβ‘(π₯2 + 5) y = sin (x2 + 5) We need to find derivative of π¦, π€.π.π‘.π₯ (ππ¦ )/ππ₯ = (π(sinβ‘(π₯2 + 5)))/ππ₯ = cos (π₯2 + 5) Γ π(π₯2 + 5)/ππ₯ = cos (π₯2 + 5) Γ ((π(π₯2))/ππ₯+ (π(5))/ππ₯) = cos (π₯2 + 5) Γ (γ2π₯γ^(2β1) + 0) = cos (π₯2 + 5) Γ 2π₯ = ππ πππβ‘γ (ππ + π)γ
