Last updated at April 16, 2024 by Teachoo
Ex 5.2, 8 Differentiate the functions with respect to π₯ cos (βπ₯) Let π¦ = " cos " (βπ₯) We need to find derivative of π¦ π€.π.π‘.π₯ i.e. ππ¦/ππ₯ = π(cosβ‘βπ₯ )/ππ₯ = βsin βπ₯ . (π(βπ₯))/ππ₯ = βsin βπ₯ . 1/(2βπ₯) = (βπ¬π’π§β‘βπ)/(πβπ)