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Ex 5.2, 4 Differentiate the functions with respect to x sec (tan ( √π‘₯ )) Let 𝑦 = sec (tan √π‘₯ ) We need to find Derivative of 𝑦 i.e. 𝑦’ = (sec⁑〖〖(tanγ€—β‘βˆšπ‘₯)γ€— )^β€² = γ€–π¬πžπœ 〗⁑〖(π­πšπ§β‘βˆšπ’™)γ€— γ€–π­πšπ§ 〗⁑〖(π’•π’‚π’β‘βˆšπ’™)γ€— (tan⁑√π‘₯ )^β€² = γ€–sec 〗⁑〖(tan⁑√π‘₯)γ€— γ€–tan 〗⁑〖(tan⁑√π‘₯)γ€—. ("sec2 " √π‘₯ " . " (√π‘₯)^β€²) = γ€–sec 〗⁑〖(tan⁑√π‘₯)γ€— γ€–tan 〗⁑〖(tan⁑√π‘₯)γ€—. sec2 " " √π‘₯ Γ— 1/(2√π‘₯) = (𝒔𝒆𝒄⁑〖(π’•π’‚π’β‘βˆšπ’™ γ€—)𝒔𝒆𝒄⁑〖(π’•π’‚π’β‘βˆšπ’™ γ€—)〖𝒔𝒆𝒄〗^πŸβ‘βˆšπ’™ )/(πŸβˆšπ’™)

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.