Ex 10.2, 16 - Chapter 10 Class 12 Vector Algebra

Transcript

Ex 10.2, 16 Find the position vector of the mid point of the vector joining the points P(2, 3, 4) and Q(4, 1, –2). P(2,3,4) , Q(4, 1, −2) Let the midpoint of PQ be R. Position vector of P = (2 − 0) 𝑖﷯ + (3 − 0) 𝑗﷯ + (4 − 0) 𝑘﷯ 𝑂𝑃﷯ = 2 𝑖﷯ + 3 𝑗﷯ + 4 𝑘﷯ Position vector of Q = (4 − 0) 𝑖﷯ + (1 − 0) 𝑗﷯ + (−2 − 0) 𝑘﷯ 𝑂𝑄﷯ = 4 𝑖﷯ + 1 𝑗﷯ − 2 𝑘﷯ Position vector of R = 𝑶𝑸﷯ + 𝑶𝑷﷯﷮𝟐﷯ 𝑂𝑅﷯ = 4 𝑖﷯ + 1 𝑗﷯ − 2 𝑘﷯﷯ + (2 𝑖﷯ + 3 𝑗﷯ + 4 𝑘﷯)﷮2﷯ 𝑂𝑅﷯ = 4 + 2﷯ 𝑖﷯ + 1 + 3﷯ 𝑗﷯ + (−2 + 4) 𝑘﷯﷮2﷯ 𝑂𝑅﷯ = 6 𝑖﷯ + 4 𝑗﷯ + 2 𝑘﷯﷮2﷯ 𝑂𝑅﷯ = 2(3 𝑖﷯ + 2 𝑗﷯ + 𝑘﷯)﷮2﷯ 𝑂𝑅﷯ = 𝟑 𝒊﷯+𝟐 𝒋﷯+ 𝒌﷯ Therefore, position vector of midpoint of PQ is 3 𝑖﷯ + 2 𝑗﷯ + 𝑘﷯