Ex 10.2

Chapter 10 Class 12 Vector Algebra
Serial order wise

### Transcript

Ex 10.2, 10 Find a vector in the direction of vector 5π Μ β π Μ + 2π Μ which has magnitude 8 units.π β = 5π Μ β π Μ + 2π Μ = 5π Μ β 1π Μ + 2π Μ Magnitude of π β = β(52+(β1)2+22) |π β | = β(25+1+4) = β30 Unit vector in direction of π β = 1/|π β | . π β π Μ = 1/β30 . [5π Μβ1π Μ+2π Μ ] π Μ = 5/β30 π Μ β 1/β30 π Μ + 2/β30 π Μ Thus, unit vector π Μ = 5/β30 π Μ β 1/β30 π Μ + 2/β30 π Μ Vector with magnitude 1 = 5/β30 π Μ β 1/β30 π Μ + 2/β30 π Μ Vector with magnitude 8 = 8 [5/β30 π Μ" β " 1/β30 π Μ" + " 2/β30 π Μ ] = ππ/βππ π Μ β π/βππ π Μ + ππ/βππ π Μ Hence, the required vector is 40/β30 π Μ β 8/β30 π Μ + 16/β30 π Μ

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#### Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.