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Last updated at April 21, 2021 by Teachoo

Transcript

Ex 10.2, 14 Show that the vector ๐ ฬ + ๐ ฬ + ๐ ฬ is equally inclined to the axes OX, OY and OZ. Let ๐ โ = ๐ ฬ + ๐ ฬ + ๐ ฬ = 1๐ ฬ + 1๐ ฬ + 1๐ ฬ A vector is equally inclined to OX, OY, OZ i.e. X, Y and Z axes respectively, if its direction cosines are equal. Direction ratios of ๐ โ are ๐ = 1, b = 1 , c = 1 Magnitude of ๐ โ = โ(12+12+12) |๐ โ | = โ(1+1+1) = โ3 Direction cosines OF ๐ โ are (๐/|๐ โ | ,๐/|๐ โ | ,๐/|๐ โ | ) = (1/โ3,1/โ3,1/โ3) Since the direction cosines are equal, ๐ โ = ๐ ฬ + ๐ ฬ + ๐ ฬ is equally inclined to OX, OY and OZ

Ex 10.2

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Ex 10.2, 14 You are here

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Ex 10.2, 18 (MCQ) Important

Ex 10.2, 19 (MCQ) Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.