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Ex 10.2

Ex 10.2, 1

Ex 10.2, 2 You are here

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Ex 10.2, 18 (MCQ) Important

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Last updated at March 22, 2023 by Teachoo

Ex 10.2, 2 Write two different vectors having same magnitude. Let us take two different vectors, π β = 2π Μ + π Μ + π Μ = 2π Μ + 1π Μ + 1π Μ And π β = π Μ + π Μ + 2π Μ = 1π Μ + 1π Μ + 2π Μ Magnitude of π β = β(22+12+12) |π β | = β(4+1+1) = β6 Magnitude of π β = β(12+12+22) |π β | = β(1+1+4) = β6 β΄ Magnitude of π β = Magnitude of π β = β6 Thus two different vectors having the same magnitude are π β = 2π Μ + π Μ + π Μ and π β = π Μ + π Μ + 2π Μ