![Ex 10.2, 2 - Chapter 10 Class 12 Vector Algebra - Part 2](https://d1avenlh0i1xmr.cloudfront.net/f57f9c1d-9141-4f46-ade8-5133b3a9079a/slide4.jpg)
Ex 10.2
Last updated at April 16, 2024 by Teachoo
Ex 10.2, 2 Write two different vectors having same magnitude. Let us take two different vectors, π β = 2π Μ + π Μ + π Μ = 2π Μ + 1π Μ + 1π Μ And π β = π Μ + π Μ + 2π Μ = 1π Μ + 1π Μ + 2π Μ Magnitude of π β = β(22+12+12) |π β | = β(4+1+1) = β6 Magnitude of π β = β(12+12+22) |π β | = β(1+1+4) = β6 β΄ Magnitude of π β = Magnitude of π β = β6 Thus two different vectors having the same magnitude are π β = 2π Μ + π Μ + π Μ and π β = π Μ + π Μ + 2π Μ