Last updated at Jan. 3, 2020 by Teachoo

Transcript

Ex 10.2, 9 For given vectors, 𝑎 = 2 𝑖 − 𝑗 + 2 𝑘 and 𝑏 = − 𝑖 + 𝑗 − 𝑘 , find the unit vector in the direction of the vector 𝑎 + 𝑏 𝑎 = 2 𝑖 − j + 2 𝑘 = 2 𝑖 – 1 𝑗 + 2 𝑘 𝑏 = − 𝑖 + 𝑗 – 𝑘 = −1 𝑖 + 1 𝑗 – 1 𝑘 Now, ( 𝑎 + 𝑏) = (2 – 1) 𝑖 + (-1 + 1) 𝑗 + (2 – 1) 𝑘 = 1 𝑖 + 0 𝑗 + 1 𝑘 Let 𝑐 = 𝑎 + 𝑏 ∴ c = 1 𝑖 + 0 𝑗 + 1 𝑘 Magnitude of 𝑐 = 12+02+12 𝑐 = 1+0+1 = 2 Unit vector in direction of 𝑐 = 1 𝑐 . 𝑐 𝑐 = 1 2 1 𝑖+0 𝑗+1 𝑘 𝑐 = 1 2 𝑖 + 0 𝑗 + 1 2 𝑘 𝑐 = 𝟏 𝟐 𝒊 + 𝟏 𝟐 𝒌 Thus, unit vector in direction of 𝑐 = 1 2 𝑖 + 1 2 𝑘

Ex 10.2

Ex 10.2, 1

Ex 10.2, 2

Ex 10.2, 3

Ex 10.2, 4 Important

Ex 10.2, 5 Important

Ex 10.2, 6

Ex 10.2, 7 Important

Ex 10.2, 8

Ex 10.2, 9 You are here

Ex 10.2, 10 Important

Ex 10.2, 11

Ex 10.2, 12

Ex 10.2, 13 Important

Ex 10.2, 14

Ex 10.2, 15 Important

Ex 10.2, 16

Ex 10.2, 17 Important

Ex 10.2, 18 Important

Ex 10.2, 19 Important

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.