# Example 14 - Chapter 3 Class 12 Matrices (Term 1)

Last updated at Dec. 8, 2016 by Teachoo

Last updated at Dec. 8, 2016 by Teachoo

Transcript

Example 14 If A = [■8(1&0@0&−1)] and B = [■8(0&1@1&0)] , find AB and BA. Prove that AB ≠ BA AB = [■8(1&0@0&−1)] [■8(0&1@1&0)] = [■8(1(0)+0 (1)&1(1)+0 (0)@0(0)+(−1)(1)&0(1)+(−1) (0))] = [■8(0+0&1+0`@0−1&0+0)] = [■8(0&1@−1&0)] BA = [■8(0&1@1&0)][■8(1&0@0&−1)] = [■8(0(1)+1(0)&0(0)+1(−1)@1(1)+0 (0)&1(0)+0 (−1))] = [■8(0+0&0−1@0+1&0+0)] = [■8(0&−1@1&0)] ≠ AB Hence AB ≠ BA Hence proved

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Example 14 You are here

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Example 23 Deleted for CBSE Board 2022 Exams

Example 24 Important Deleted for CBSE Board 2022 Exams

Example 25 Important Deleted for CBSE Board 2022 Exams

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Chapter 3 Class 12 Matrices (Term 1)

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.