# Example 9 - Chapter 3 Class 12 Matrices

Last updated at May 29, 2018 by Teachoo

Last updated at May 29, 2018 by Teachoo

Transcript

Example 9, Find X and Y , if X + Y = [■8(5&2@0&9)] and X – Y = [■8(3&6@0&−1)] It is given that X + Y = [■8(5&2@0&9)] X – Y = [■8(3& 6@0&−1)] `Adding (1) and (2) (X + Y) + (X – Y) = [■8(5&2@0&9)] + [■8(3&6@0&−1)] X + X + Y – Y = [■8(5+3&2 +6@0+0&9+( −1))] 2X = [■8(8&8@0&8)] X = 1/2 [■8(8&8@0&8)] X = [■8(8/2&8/2@0&8/2)] X = [■8(4&4@0&4)] Thus, X = [■8(4&4@0&4)] Putting X = [■8(4&4@0&4)] in (1) X + Y = [■8(5&2@0&9)] Y = [■8(5&2@0&9)] – X Y = [■8(5&2@0&9)] – [■8(4&4@0&4)] Y = [■8(5−4&2−4@0−0&9−4)] Y = [■8(1&−2@0&5)] Hence, X = [■8(4&4@0&4)], Y =[■8(1&−2@0&5)]

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About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 8 years. He provides courses for Maths and Science at Teachoo. You can check his NCERT Solutions from Class 6 to 12.