Get live Maths 1-on-1 Classs - Class 6 to 12
Example 5 - Chapter 3 Class 12 Matrices (Term 1)
Last updated at March 16, 2023 by Teachoo
Examples
Example 1
Example 2
Example 3 Important
Example 4
Example 5 Important You are here
Example 6
Example 7
Example 8
Example 9
Example 10
Example 11 Important
Example 12
Example 13 Important
Example 14
Example 15
Example 16 Important
Example 17
Example 18 Important
Example 19
Example 20 Important
Example 21
Example 22 Important
Example 23
Example 24 Important
Example 25 Important
Example 26 Important
Example 27 Important
Example 28
Chapter 3 Class 12 Matrices
Serial order wise
Transcript
Example 5 Find the values of a, b, c, and d from the following equation: [ 8(2a+b&a [email protected] d&4c+3d)] = [ 8(4& [email protected]&24)] Since matrices are equal. Their corresponding elements are equal 2a + b = 4 5c d = 11 a 2b = 3 4c + 3d = 24 Solving these equations Solving (1) 2a + b = 4 b = 4 2a Solving (3) a 2b = 3 Putting b = 4 2a a 2(4 2a) = -3 a 8 + 4a = -3 a + 4a = -3 + 8 5a = 5 a = 5/5 a = 1 From (1) 2a + b = 4 Putting a = 1 2(1) + b = 4 2 + b = 4 b = 4 2 b = 2 From (2) 5c d = 11 5c = 11 + d 5c 11 = d d = 5c 11 Solving (4) 4c + 3d = 24 Putting d = 5c 11 4c + 3(5c 11) = 24 4c + 15c 33 = 24 19c 33 = 24 19c = 24 + 33 19c = 57 c = 57/19 c = 3 Now, d = 5c 11 Putting c = 3 d = 5(3) 11 d = 15 11 d = 4 Hence , a = 1, b = 2, c = 3 and d = 4
