# Example 5 - Chapter 3 Class 12 Matrices (Term 1)

Last updated at Jan. 17, 2020 by Teachoo

Last updated at Jan. 17, 2020 by Teachoo

Transcript

Example 5 Find the values of a, b, c, and d from the following equation: [ 8(2a+b&a 2b@5c d&4c+3d)] = [ 8(4& 3@11&24)] Since matrices are equal. Their corresponding elements are equal 2a + b = 4 5c d = 11 a 2b = 3 4c + 3d = 24 Solving these equations Solving (1) 2a + b = 4 b = 4 2a Solving (3) a 2b = 3 Putting b = 4 2a a 2(4 2a) = -3 a 8 + 4a = -3 a + 4a = -3 + 8 5a = 5 a = 5/5 a = 1 From (1) 2a + b = 4 Putting a = 1 2(1) + b = 4 2 + b = 4 b = 4 2 b = 2 From (2) 5c d = 11 5c = 11 + d 5c 11 = d d = 5c 11 Solving (4) 4c + 3d = 24 Putting d = 5c 11 4c + 3(5c 11) = 24 4c + 15c 33 = 24 19c 33 = 24 19c = 24 + 33 19c = 57 c = 57/19 c = 3 Now, d = 5c 11 Putting c = 3 d = 5(3) 11 d = 15 11 d = 4 Hence , a = 1, b = 2, c = 3 and d = 4

Examples

Example 1

Example 2

Example 3

Example 4

Example 5 Important You are here

Example 6

Example 7

Example 8

Example 9

Example 10

Example 11

Example 12

Example 13

Example 14

Example 15

Example 16

Example 17

Example 18 Important

Example 19

Example 20 Important

Example 21

Example 22 Important

Example 23 Deleted for CBSE Board 2022 Exams

Example 24 Important Deleted for CBSE Board 2022 Exams

Example 25 Important Deleted for CBSE Board 2022 Exams

Example 26 Important

Example 27 Important

Example 28

Chapter 3 Class 12 Matrices (Term 1)

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 10 years. He provides courses for Maths and Science at Teachoo.