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Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class


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Example 10 Find the values of x and y from the following equation: 2[■8(𝑥&5@7&𝑦−3)] + [■8(3&−4@1&2)] = [■8(7&6@15&14)] 2[■8(𝑥&5@7&𝑦−3)] + [■8(3&−4@1&2)] = [■8(7&6@15&14)] [■8(𝑥 × 2&5 × 2@7 × 2&(𝑦−3)× 2)] + [■8(3&−4@1&2)] = [■8(7&6@15&14)] [■8(𝟐𝒙&𝟏𝟎@𝟏𝟒&𝟐𝒚 −𝟔)] + [■8(𝟑&−𝟒@𝟏&𝟐)] = [■8(𝟕&𝟔@𝟏𝟓&𝟏𝟒)] [■8(2𝑥+3&10 −4@14+1&2𝑦 −6+2)] = [■8(7&6@15&14)] [■8(𝟐𝒙+𝟑&𝟔@𝟏𝟓&𝟐𝒚 −𝟒)] = [■8(𝟕&𝟔@𝟏𝟓&𝟏𝟒)] Since matrices are equal. Corresponding elements are equal 2x + 3 = 7 & 2y – 4 = 14 Solving these equations Solving (1) 2x = 7 – 3 2x = 4 x = 4/2 x = 2 Hence x = 2 & y = 9 Solving (2) 2y – 4 = 14 2y = 14 + 4 2y = 18 y = 𝟏𝟖/𝟐 = 9

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 13 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.