
Learn in your speed, with individual attention - Teachoo Maths 1-on-1 Class
Ex 3.3
Ex 3.3, 2
Ex 3.3, 3
Ex 3.3, 4 Important You are here
Ex 3.3, 5 (i)
Ex 3.3, 5 (ii)
Ex 3.3, 6 (i)
Ex 3.3, 6 (ii) Important
Ex 3.3, 7 (i)
Ex 3.3, 7 (ii) Important
Ex 3.3, 8
Ex 3.3, 9
Ex 3.3, 10 (i) Important
Ex 3.3, 10 (ii)
Ex 3.3, 10 (iii) Important
Ex 3.3, 10 (iv)
Ex 3.3, 11 (MCQ) Important
Ex 3.3, 12 (MCQ)
Last updated at June 8, 2023 by Teachoo
Ex 3.3, 4 If A’ = [■8(−2&3@1&2)] and B = [■8(−1&0@1&2)] , then find (A + 2B)’ We need to find (A + 2B)’ Finding A A’ = [■8(−2&3@1&2)] A = (A’)’ = [■8(−𝟐&𝟏@𝟑&𝟐)] Also, B = [■8(−1&0@1&2)] 2B = 2 [■8(−1&0@1&2)] = [■8(2(−1)&2(0)@2(1)&2(2))] = [■8(−𝟐&𝟎@𝟐&𝟒)] Now A + 2B = [■8(−2&1@3&2)] + [■8(−2&0@2&4)] = [■8(2+(−2)&1+0@3+2&2+4)] = [■8(𝟎&𝟏@𝟓&𝟔)] ∴ (A + 2B) = [■8(−4&1@5&6)] So, (A + 2B)’ = [■8(−𝟒&𝟓@𝟏&𝟔)]