Check sibling questions

Ex 3.3, 3 - If A' = [3 4 -1 2 0 1], then verify (i) (A + B)'

Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 2
Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 3
Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 4

This video is only available for Teachoo black users

Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 5

Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 6
Ex 3.3, 3 - Chapter 3 Class 12 Matrices - Part 7

 

 

 

Solve all your doubts with Teachoo Black (new monthly pack available now!)


Transcript

Ex 3.3,3 If A’ = [■8(3&4@−1&2@0&1)] and B =[■8(−1&2&1@1&2&3)] , then verify that (i) (A + B)’ = A’ + B’ Solving L.H.S (A + B)’ First finding A + B Given A’ = [■8(3&4@−1&2@0&1)] A = (A’)’ = [■8(3&4@−1&2@0&1)]^′ = [■8(3&−1&0@4&2&1)] Now, A + B = [■8(3&−1&0@4&2&1)] + [■8(−1&2&1@1&2&3)] = [■8(3+(−1)&−1+2&0+1@4+1&2+2&1+3)] = [■8(2&1&1@5&4&4)] So, (A + B)’ = [■8(2&5@1&4@1&4)] Solving R.H.S. (A’ + B’) Given A’ = [■8(3&4@−1&2@0&1)] Also B = [■8(−1&2&1@1&2&3)] B’ = [■8(−1&1@2&2@1&3)] A’ + B’ = [■8(3&4@−1&2@0&1)] + [■8(−1&1@2&2@1&3)] = [■8(3+(−1)&4+1@−1+2&2+2@0+1&1+3)] = [■8(2&5@1&4@1&4)] = L.H.S Hence, L.H.S = R.H.S Hence proved Ex 3.3, 3 If A’ = [■8(3&4@−1&2@0&1)] and B =[■8(−1&2&1@1&2&3)] , then verify that (ii) (A – B)’ = A’ – B’ Solving L.H.S (A – B)’ First finding A – B A – B = [■8(3&−1&0@4&2&1)] – [■8(−1&2&1@1&2&3)] = [■8(3−(−1)&−1−2&0−1@4−1&2−2&1−3)] = [■8(3+1&−3&−1@3&0&−2)] = [■8(4&−3&−1@3&0&−2)] (A – B)’ = [■8(4&3@−3&0@−1&−2)] Solving R.H.S A’ – B’ Given A’ = [■8(3&4@−1&2@0&1)] B = [■8(−1&2&1@1&2&3)] B’ = [■8(−1&1@2&2@1&3)] A’ – B’ = [■8(3&4@−1&2@0&1)] – [■8(−1&1@2&2@1&3)] = [■8(3−(−1)&4−1@−1−2&2−2@0−1&1−3)] = [■8(3+1&3@−3&0@−1&−2)] = [■8(4&3@−3&0@−1&−2)] = L.H.S Hence, L.H.S = R.H.S Hence proved

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.