Finding New Algebraic Identities
Last updated at May 18, 2026 by Teachoo
Transcript
Sum and Difference of Cubes SUM OF TWO CUBES FORMULA Example: ā (8a^3+27=(2a)^3+3^3@=(2a+3)(4a^2-6a+9) ) DIFFERENCE OF TWO CUBES FORMULA x^3-y^3=(x-y)(x^2+xy+y^2 ) Factors into: (x-y)" and " (x^2+xy+y^2 ) Example: (&27x^3-64=(3x)^3-4^3@=& (3x-4)(9x^2+12x+16) ) š^š+š^š ššššššš Our identity is š^š+š^š=(š+š)(š^šāšš+š^š ) We can prove this using algebra (š+š)(š^šāšš+š^š ) =š„(š„^2āš„š¦+š¦^2 )+š¦(š„^2āš„š¦+š¦^2 ) =(š„^3āš„^2 š¦+š„š¦^2 )+(š„^2 š¦āš„š¦^2+š¦^3 ) =š„^3āš„^2 š¦+š„š¦^2+š„^2 š¦āš„š¦^2+š¦^3 =š^š+š^š š^šāš^š ššššššš Our identity is š^šāš^š=(šāš)(š^š+šš+š^š ) We can prove this using algebra (šāš)(š^š+šš+š^š ) =š„(š„^2+š„š¦+š¦^2 )āš¦(š„^2+š„š¦+š¦^2 ) =(š„^3+š„^2 š¦+š„š¦^2 )ā(š„^2 š¦+š„š¦^2+š¦^3 ) =š„^3+š„^2 š¦+š„š¦^2āš„^2 š¦āš„š¦^2āš¦^3 =š^šāš^š