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Example 13 - Chapter 4 Class 9 - Exploring Algebraic Identities (Ganita Manjari I)
Last updated at May 18, 2026 by Teachoo
Class 9
Chapter 4 Class 9 - Exploring Algebraic Identities (Ganita Manjari I)
- Consecutive Square Numbers
- Visualising Algebraic Identities
- Exercise Set 4.1
- Factorisation of Algebraic Expressions Using Identities
- Exercise Set 4.2
- More Identities
- Exercise Set 4.3
- Rewriting a2 - b2 Identity
- Factorisation Using Algebra Tiles
- Factorisation by Splitting the Middle term
- Exercise Set 4.4
-
Finding New Algebraic Identities
- Simplifying Rational Expressions
- Exercise Set 4.5
- Word Problems
- End-of-Chapter Exercises
Transcript
Example 13 What is the side of the cube whose volume is π^3+6π^2 π+12ππ^2 + 8π^3 cubic units? Now, Volume of cube = γπΊππ πγ^π We need to factorise the given expression into a cube form Given expression π^π+ππ^π π+ππππ^π+ ππ^π Here, There are 2 cube terms: π^3=(π)^3 and 8π^3=(2π)^3 Our other terms are positive So we use (a + b)3 Now, π^3+6π^2 π+12ππ^2+ 8π^3 = π^3+ 8π^3+6π^2 π+12ππ^2 = γ(π)γ^π+(ππͺ)^π+π Γ π©^π Γ ππͺ+π Γ π© Γ (ππͺ)^π = (π+ππ)^π Thus, Side of cube with given volume is π+ππ Using (π+π)^3=π^3+π^3+3π^2 π+3ππ^2 Putting π = π, π = 2π
