Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Feb. 6, 2020 by Teachoo

Transcript

Ex 11.3, 16 Find the equation for the ellipse that satisfies the given conditions: Length of minor axis 16, foci (0, ±6) We need to find equation of ellipse whose length of minor axis = 16 & Foci = (0, ±6) Since foci is of the type (0, ±c) The major axis is along the y-axis. & required Equation of Ellipse is 𝒙^𝟐/𝒃^𝟐 + 𝒚^𝟐/𝒂^𝟐 = 1 From (1) & (2) c = 6 Given length of major axis = 16 & we know that Length of manor axis = 2b 16 = 2b 2b = 16 b = 16/2 b = 8 Also, We know that c2 = a2 − b2 (6) 2 = a 2 − (8)2 (6) 2 + (8)2 = a 2 36 + 64 = a 2 100 = a2 a2 = 100 Equation of ellipse is 𝑥^2/𝑏^2 + 𝑦^2/𝑎^2 = 1 Putting values 𝑥^2/〖(8)〗^2 + 𝑦^2/100 = 1 𝒙^𝟐/𝟔𝟒 + 𝒚^𝟐/𝟏𝟎𝟎 = 1

Ex 11.3

Ex 11.3, 1

Ex 11.3, 2

Ex 11.3, 3

Ex 11.3, 4

Ex 11.3, 5 Important

Ex 11.3, 6

Ex 11.3, 7

Ex 11.3, 8

Ex 11.3, 9

Ex 11.3, 10

Ex 11.3, 11 Important

Ex 11.3, 12 Important

Ex 11.3, 13

Ex 11.3, 14 Important

Ex 11.3, 15

Ex 11.3, 16 Important You are here

Ex 11.3, 17

Ex 11.3, 18 Important

Ex 11.3, 19 Important

Ex 11.3, 20

Chapter 11 Class 11 Conic Sections

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.