Check sibling questions

Ex 11.3, 16 - Find equation: Length Minor axis 16, foci (0, 6)

Ex 11.3,  16 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.3,  16 - Chapter 11 Class 11 Conic Sections - Part 3


Transcript

Ex 11.3, 16 Find the equation for the ellipse that satisfies the given conditions: Length of minor axis 16, foci (0, ±6) We need to find equation of ellipse whose length of minor axis = 16 & Foci = (0, ±6) Since foci is of the type (0, ±c) The major axis is along the y-axis. & required Equation of Ellipse is 𝒙^𝟐/𝒃^𝟐 + 𝒚^𝟐/𝒂^𝟐 = 1 From (1) & (2) c = 6 Given length of major axis = 16 & we know that Length of manor axis = 2b 16 = 2b 2b = 16 b = 16/2 b = 8 Also, We know that c2 = a2 − b2 (6) 2 = a 2 − (8)2 (6) 2 + (8)2 = a 2 36 + 64 = a 2 100 = a2 a2 = 100 Equation of ellipse is 𝑥^2/𝑏^2 + 𝑦^2/𝑎^2 = 1 Putting values 𝑥^2/〖(8)〗^2 + 𝑦^2/100 = 1 𝒙^𝟐/𝟔𝟒 + 𝒚^𝟐/𝟏𝟎𝟎 = 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.