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Ex 11.4, 1 - x2/16 - y2/9 = 1 Find foci, vertices - Hyperbola

Ex 11.4,  1 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.4,  1 - Chapter 11 Class 11 Conic Sections - Part 3

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Transcript

Ex 11.4, 1 Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola x2 16 - y2 9 = 1 Given equation is 2 16 2 9 = 1 The above equation is of the form 2 2 2 2 = 1 So axis of hyperbola is x-axis , Comparing (1) & (2) a2 = 16 a = 4 & b2 = 9 b = 3 Now, c2 = a2 + b2 c2 = 16 + 9 c2 = 25 c = 5 Co-ordinate of foci = ( c, 0) = ( 5, 0) Hence co-ordinates of foci are (5, 0) & ( 5, 0) Co-ordinate of vertices = ( a, 0) = ( 4,0) So, co-ordinates of vertices are (4, 0) & ( 4, 0) Eccentricity = e = = 5 4 Latus rectum = 2 2 = 2(9) 4 = 9 2

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Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.