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Ex 11.4, 10 - Find hyperbola: foci (5, 0), transverse 8 - Hyperbola

Ex 11.4,  10 - Chapter 11 Class 11 Conic Sections - Part 2
Ex 11.4,  10 - Chapter 11 Class 11 Conic Sections - Part 3


Transcript

Ex 11.4, 10 Find the equation of the hyperbola satisfying the given conditions: Foci ( 5, 0), the transverse axis is of length 8. Co-ordinates of foci is ( 5, 0) Which is of form ( c, 0) Hence c = 5 Also , foci lies on the x-axis So, Equation of hyperbola is 2 2 2 2 = 1 We know that c2 = a2 + b2 Putting c = 5 25 = a2 + b2 a2 + b2 = 25 Now Transverse axis is of length 8 and we know that Length of traverse axis = 2a 2a = 8 a = 8 2 a = 4 So, a2 = (4)2= 16 Putting value of a2 in (1) a2 + b2 = 25 (16) + b2 = 25 b2 = 25 16 b2 = 9 Required equation of hyperbola 2 2 2 2 = 1 Putting value of a2 & b2 = 1

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Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 12 years. He provides courses for Maths, Science, Social Science, Physics, Chemistry, Computer Science at Teachoo.