Ex 11.4, 10 - Chapter 11 Class 11 Conic Sections
Last updated at May 29, 2018 by Teachoo
Last updated at May 29, 2018 by Teachoo
Transcript
Ex 11.4, 10 Find the equation of the hyperbola satisfying the given conditions: Foci ( 5, 0), the transverse axis is of length 8. Co-ordinates of foci is ( 5, 0) Which is of form ( c, 0) Hence c = 5 Also , foci lies on the x-axis So, Equation of hyperbola is 2 2 2 2 = 1 We know that c2 = a2 + b2 Putting c = 5 25 = a2 + b2 a2 + b2 = 25 Now Transverse axis is of length 8 and we know that Length of traverse axis = 2a 2a = 8 a = 8 2 a = 4 So, a2 = (4)2= 16 Putting value of a2 in (1) a2 + b2 = 25 (16) + b2 = 25 b2 = 25 16 b2 = 9 Required equation of hyperbola 2 2 2 2 = 1 Putting value of a2 & b2 = 1
Ex 11.4
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