Slide10.JPG Slide11.JPG Slide12.JPG Slide13.JPG

You saved atleast 2 minutes by viewing the ad-free version of this page. Thank you for being a part of Teachoo Black.


Transcript

Ex 10.4, 4 Find the coordinates of the foci and the vertices, the eccentricity, and the length of the latus rectum of the hyperbola 16x2 9y2 = 576 The given equation is 16x2 9y2 = 576. Dividing whole equation by 576 16 2 576 9 2 576 = 576 576 2 36 2 64 = 1 The above equation hyperbola is of the form 2 2 2 2 = 1 Axis of hyperbola is x axis Comparing (1) & (2) a2 = 36 a = 6 & b2 = 64 b = 8 Also, c2 = a2 + b2 c2 = 36 + 64 c2 = 100 c = 10 Co-ordinates of foci = ( c, 0) = ( 10, 0) So co-ordinate of foci are (10, 0) & ( 10, 0) Vertices = ( a, 0) = ( 6, 0) So, co-ordinates vertices are (6, 0) & ( 6, 0) Eccentricity e = = 10 6 = 5 3 Latus rectum = 2 2 = 2 64 6 = 64 3

Davneet Singh's photo - Co-founder, Teachoo

Made by

Davneet Singh

Davneet Singh has done his B.Tech from Indian Institute of Technology, Kanpur. He has been teaching from the past 14 years. He provides courses for Maths, Science and Computer Science at Teachoo