Ex 11.4, 11 - Find hyperbola: foci (0, 13), conjugate axis 24 - Hyperbola

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  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise

Transcript

Ex 11.4, 11 Find the equation of the hyperbola satisfying the given conditions: Foci (0, 13), the conjugate axis is of length 24. We need to find equation of hyperbola given foci (0, 13) & conjugate axis is of length 24. Since foci is on the y axis So required equation of hyperbola is 2 2 2 2 = 1 Now, Co-ordinates of foci = (0, c) & given foci = (0, 13) So, (0, c) = (0, 13) c = 13 Length of conjugate axis = 2b Given length of conjugate axis = 24 So, 2b = 24 b = 24 2 b = 12 We know that c2 = a2 + b2 Putting Values (13)2= a2 + (12)2 (13)2 (12)2 = a2 169 144 = a2 25 = a2 a2 = 25 Thus, the required equation of ellipse 2 2 2 2 =1 2 25 2 12 2 =1 =1

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