Subscribe to our Youtube Channel - https://you.tube/teachoo

Last updated at Feb. 6, 2020 by Teachoo

Transcript

Ex 11.3, 14 Find the equation for the ellipse that satisfies the given conditions: Ends of major axis (0, ± √5) , ends of minor axis (±1, 0) Given ends of Major Axis (0, ± √5), & ends of Minor Axis (±1, 0) Major axis is along the y-axis So, our required equation of ellipse is 𝒙^𝟐/𝒃^𝟐 + 𝒚^𝟐/𝒂^𝟐 = 1 We know that End of major axis is the vertices of the ellipse So vertices of ellipse = (0, ± √5) Also, Vertices of the ellipse is (0, ± a) Comparing (0, ± a) = (0, ± √5) a = √𝟓 We know that End of minor axis = (± b, 0) So, (±1, 0) = (± b, 0) So, b = 1 Required equation of ellipse is 𝑥^2/𝑏^2 + 𝑦^2/𝑎^2 = 1 Putting values 𝑥^2/1^2 + 𝑦^2/(√5)^2 = 1 𝒙^𝟐/𝟏 + 𝒚^𝟐/𝟓 = 1

Ex 11.3

Ex 11.3, 1

Ex 11.3, 2

Ex 11.3, 3

Ex 11.3, 4

Ex 11.3, 5 Important

Ex 11.3, 6

Ex 11.3, 7

Ex 11.3, 8

Ex 11.3, 9

Ex 11.3, 10

Ex 11.3, 11 Important

Ex 11.3, 12 Important

Ex 11.3, 13

Ex 11.3, 14 Important You are here

Ex 11.3, 15

Ex 11.3, 16 Important

Ex 11.3, 17

Ex 11.3, 18 Important

Ex 11.3, 19 Important

Ex 11.3, 20

Chapter 11 Class 11 Conic Sections

Serial order wise

About the Author

Davneet Singh

Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.