Ex 11.3, 10 - Chapter 11 Class 11 Conic Sections (Term 2)
Last updated at Dec. 8, 2016 by Teachoo
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Ex 11.3, 10 You are here
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Last updated at Dec. 8, 2016 by Teachoo
Ex 11.3, 10 Find the equation for the ellipse that satisfies the given conditions: Vertices (±5, 0), foci (±4, 0) Given Vertices (±5, 0) Since the vertices are of form (± a, 0) Hence, Major axis is along x-axis and equation of ellipse is 𝑥2𝑎2 + 𝑦2𝑏2 = 1 From (1) & (2) a = 5 Also given coordinate of foci = (±4, 0) We know that foci = (± c, 0) So c = 4 We know that c2 = a2 − b2 (4) 2 = (5) 2 − b2 b2 = (5) 2 − (4) 2 b2 = 25 − 16 b2 = 9 b = 9 b = 3 Hence b = 3 Equation of ellipse is 𝑥2𝑎2 + 𝑦2𝑏2 = 1 Putting value 𝑥2(5)2 + 𝑦2(3)2 = 1 𝑥225 + 𝑦29 = 1 Which is required equation