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Last updated at Feb. 6, 2020 by Teachoo
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Ex 11.3, 5 Find the coordinates of the foci, the vertices, the length of major axis, the minor axis, the eccentricity and the length of the latus rectum of the ellipse x2/49 + y2/36 = 1 ๐ฅ^2/49 + ๐ฆ^2/36 = 1 Since 49 > 36 Hence the above equation is of the form ๐ฅ^2/๐^2 + ๐ฆ^2/๐^2 = 1 Comparing (1) & (2) We know that c = โ(a2โb2) c = โ(49โ36) c = โ๐๐ Coordinate of foci = (ยฑ c, 0) = (ยฑ โ๐๐, 0) So coordinate of foci are (โ13, 0), (โโ13, 0) Vertices = (ยฑ a, 0) = (ยฑ7, 0) So vertices are (7, 0) & (โ7, 0) Length of major axis = 2a = 2 ร 7 = 14 Length of minor axis = 2b = 2 ร 6 = 12 Eccentricity e = ๐/๐ = โ๐๐/๐ Latus rectum = (2๐^2)/๐ = (2 ร 36)/7 = ๐๐/๐
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