Slide31.JPG

Slide32.JPG
Slide33.JPG

Subscribe to our Youtube Channel - https://you.tube/teachoo

  1. Chapter 11 Class 11 Conic Sections
  2. Serial order wise

Transcript

Ex 11.3, 11 Find the equation for the ellipse that satisfies the given conditions: Vertices (0, ยฑ13), foci (0, ยฑ5) Given Vertices (0, ยฑ13) Hence The vertices are of the form (0, ยฑa) Hence, the major axis is along y-axis & Equation of ellipse is of the form ๐’™^๐Ÿ/๐’ƒ^๐Ÿ + ๐’š^๐Ÿ/๐’‚^๐Ÿ = 1 From (1) & (2) a = 13 Also given coordinate of foci = (0, ยฑ5) We know that foci are = (0, ยฑc) So c = 5 We know that c2 = a2 โˆ’ b2 (5) 2 = (13) 2 โˆ’ b2 b2 = (13) 2 โˆ’ (5) 2 b2 = 169 โˆ’ 25 b2 = 144 Equation of ellipse is ๐‘ฅ^2/๐‘^2 + ๐‘ฆ^2/๐‘Ž^2 = 1 Putting value ๐’™^๐Ÿ/๐Ÿ๐Ÿ’๐Ÿ’ + ๐’š^๐Ÿ/๐Ÿ๐Ÿ”๐Ÿ— = 1 Equation of ellipse is ๐‘ฅ^2/๐‘^2 + ๐‘ฆ^2/๐‘Ž^2 = 1 Putting value ๐’™^๐Ÿ/๐Ÿ๐Ÿ’๐Ÿ’ + ๐’š^๐Ÿ/๐Ÿ๐Ÿ”๐Ÿ— = 1

About the Author

Davneet Singh's photo - Teacher, Computer Engineer, Marketer
Davneet Singh
Davneet Singh is a graduate from Indian Institute of Technology, Kanpur. He has been teaching from the past 9 years. He provides courses for Maths and Science at Teachoo.